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The Analysis of Mass Density

By Gregory Bailey,2014-04-13 10:48
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The Analysis of Mass Density

    The Analysis of Mass Density Technical Physics PHY-110

    Kevin Kimball

    Binshan Zheng

    27/09/10

    Proposal

    Using given formulas, this lab has the following goals:

    1. Determining the Mass of Aluminum

    2. Determining the mass density of water

    List of Equipment

    ;250ml Graduated CYL m2ml Inc ; Triple Beam Metric Scale ;25ml Graduated CYL m1ml Inc

    ; Certain amount of Aluminum ; Certain amount of water ;some unknown material

    Procedure #1

    Determining the Mass of Aluminum 1. Fill 250ml graduated cylinder with water and read the volume (130 cc) pic1 2. Put the aluminum into the graduated cylinder and read the volume (164 cc) pic2 3. Calculate the volume of the aluminum and predict the mass of the aluminum

    4. Weigh out the actual mass of the aluminum, then compare with the predicted mass pic3

     Pic1 Pic2 Pic3

    Calculations

    3V=130 cm (water)

    3V164 cm (water+AL)=

    3V= 164 130 = 34 cm (AL)

    33D=2.7*10 kg/m (AL)

    )))?,;,?!,??!?!,?,;,?!,? * * = )?)?)!?!,~?!??!,?

    ?,;,?!,?? ? = ?))!,?(;~?

    662.7*10*34 = x*10

    X= 91.8g

    Conclusion

    Our prediction of the mass of certain AL is 91.8g but the actual mass of it is 94.5g thats

    2.9% error. I think the reasons of that are:

    ; There are certain air bubbles in the graduated cylinder when we read it, which

    affects the volume of AL

    ; We didnt dry AL enough so we weight out the AL and the water with it, which

    affects the actual mass of AL

    Procedure #2

    Determining the mass density of water 1. Weight out the mass of the 25ml Graduated cylinder (71g)pic1

    2. Fill the 25ml graduated cylinder with certain amount of water then read the

    volume(20cc) pic2

    3. Weight out he mass of the 25ml graduated cylinder with the water inside(90.8g) pic3 4. Calculate the mass of the water, then calculate the mass density of the water

     pic1 pic2 pic3

    Calculations

    M = 71g (tool)

    M = 90.8g (tool+H2O)

    M = 90.8 71= 19.8g (H2O)

    3V = 20 cm (H2O)

    ?))!;;:?!,~?!??!;;:?!,??3 3D = * * = = 0.99*10kg/m H2O)))(),,~?!?!,?,,?!,?

    Conclusion

    3333We know the mass density of water is 10 kg/m. But our result is 0.99*10 kg/m. The

    error is 1%. I think the reason is:

    ; There are certain air bubbles in the graduated cylinder when we read it, which

    3affects the volume of water. If the volume of bubbles and water are 20cm, the

    33volume of water must less than 20cm, it could be 19.8cm so it can make

    33perfect sense that mass density of water is 10 kg/m.

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