By Jim Hawkins,2014-12-06 03:43
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11.80: a) The torque exerted by the cable about the left end is . For any angle TLsinθ

     so the tension T will be the same for either angle. The horizontal , sin(180;θ)sinθ,

    component of the force that the pivot exerts on the boom will be

    1T α ,. b) From the result of part (a), and this T cosθ or Tcos (180;);Tcosθsinθ

    becomes infinite as Also, c), the tension is a minimum when is a 0 or 180.sin

    maximum, or a vertical string. d) There are no other horizontal forces, so for the 90,

    boom to be in equilibrium, the pivot exerts zero horizontal force on the boom.

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